Question

solve for candy
1/x-1/y=2 and 3/x+4/y=-1​

Answer 1

Answer:

$\boxed{x=1,y=-1}$

Step-by-step explanation:

$\implies \frac{1}{x}-\frac{1}{y}=2 \\\\ \frac{y-x}{xy}=2 \\\\ y-x=2xy ---- [1]\\\\ \implies \frac{3}{x}+\frac{4}{y}=-1 \\\\ \frac{3y+4x}{xy}=-1 \\\\ 3y+4x=-xy \\\\ -3y-4x=xy ---- [2] \\\\ substitute \ value \ of \ xy \ in \ equ.[1] \\\\ =>y-x=2xy \\ y-x=2(-3y-4x) \\ y-x=-6y-8x \\y+6y=x-8x \\7y=-7x \\ \boxed{y=-x} \\\\ substitute \ value \ of \ y \ in \ any \ equation. \\ y-x=2xy \\ -x-x=2x(-x) \\ -2x=-2x^2 \\ x^2=x \\ \boxed{x=1} \\\\ =>y=-x\\ \boxed{y=-1}$