Question

solve for n and find the value

Answer 1

2n is even and 2n+1 and also 4n+1 is odd

Answer 2

$Given : (-1) + (-1)^{2n} + (-1)^{2n+1} + (-1)^{4n+1}$

Given that n is any positive odd integer.

$(-1)^1 + (-1)^2 + (-1)^3 + (-1)^5$

-1 + 1 - 1 - 1

-2.


Hope this helps!