Math, asked by Dakshitaa, 1 year ago

solve for q :
q^2+22q+25

Answers

Answered by yadavpooja82127
0
q {}^{2} + 22q + 25 = 0 \\
let's take factor of 25
then, they are
+/-1,+/-5,+/-25

just put one by one this value as p(+/-x)
then
 - 5 {}^{2} + 22 \times ( - 5) + 25 = 0 \\ 25 + 110 + 25 = 0 \\ that \: i s \: also \: not \: possible \:
that's hit and trial method so use this you will get it ..if you will take it's factor and do surely you can do

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