solve for r:6r/7/2 =4r/2r+5/3
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$\frac{9-r^2}{r^2-2r-3}\cdot\frac{4-4r^2}{r^2+4r+3}=\ frac{4\left(r-1\right)}{r+1}$9− r 2 r 2−2 r −3 ·4−4 r 2 r 2+ 4 r +3 =4( r −1) r +1. Steps.
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