Question

. Solve for the discriminant of y² – 11y = -6 * 1 point

Answer 1

Answer:

Hey Bro.Let me solve this for you.We have to find the discriminant in the quadratic formula of a quadratic equation.It is of course b^2-4ac.

The quadratic equation is

y^2-11y+6 =0

Here,a = 1,b = -11 and c = 6.

b^2-4ac = (-11)^2- 4(1)(6)=121-24=97

Therefore,answer is 97.

Answer 2

Given: The quadratic equation $y^2-11y=-6$

To find: The discriminant for the equation $y^2-11y=-6$

Solution:

The quadratic equation is given as $y^2-11y=-6$

Rearranging the quadratic equation, $y^2-11y+6=0$

The formula for the discriminant of the quadratic equation is,

$D=b^2-4ac$

The value of $a=1,b=-11,c=6$

∴ The value of the discriminant of the quadratic equation is,

$D=b^2-4ac$

$D=(-11)^2-4*1*6$

$D=121-24$

$D=97$

From the value of the discriminant, it is seen that the value is positive therefore we can say that the roots of the equation are real roots.

Final answer:

The value of the discriminant of the quadratic equation is $97$.