Question

Solve for theta. 2sinthetacostheta = 2-sintheta + 4costheta. Correct answer will be marked brainliest. Spam reported.​

Answer 1

Answer:

4 cos(θ) + 2 sin(θ) = cos(θ)

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)Divide both sides by cos(θ):

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)Divide both sides by cos(θ):2 tan(θ) = -3

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)Divide both sides by cos(θ):2 tan(θ) = -3Divide both sides by 2:

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)Divide both sides by cos(θ):2 tan(θ) = -3Divide both sides by 2:tan(θ) = -3/2

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)Divide both sides by cos(θ):2 tan(θ) = -3Divide both sides by 2:tan(θ) = -3/2Take the inverse tangent of both sides:

4 cos(θ) + 2 sin(θ) = cos(θ)Subtract cos(θ) from both sides:3 cos(θ) + 2 sin(θ) = 0Subtract 3 cos(θ) from both sides:2 sin(θ) = -3 cos(θ)Divide both sides by cos(θ):2 tan(θ) = -3Divide both sides by 2:tan(θ) = -3/2Take the inverse tangent of both sides:Answer: θ = π n - tan^(-1)(3/2) for n element Z

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Answer 2

Step-by-step explanation:

$Given that sinθ+cosθ=1</p><p>now squaring both side we have</p><p>(sinθ+cosθ) </p><p>2</p><p> =1 </p><p>2</p><p> </p><p>sin </p><p>2</p><p> θ+cos </p><p>2</p><p> θ+2sinθcosθ=1</p><p>1+2sinθcosθ=1 (sin </p><p>2</p><p> θ+cos </p><p>2</p><p> θ=1)</p><p>2sinθcosθ=0</p><p>sin2θ=0$