sum of square of "n" first or consecutive square natural numbers
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Step-by-step explanation:
If we need to calculate the sum of squares of n consecutive natural numbers, the formula is Σn2 = n×(n+1)×(2n+1)6 n × ( n + 1 ) × ( 2 n + 1 ) 6 . It is easy to apply the formula when the value of n is known. Let us prove this true using the known algebraic identity.
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