Question

solve for value of x and y if 5 x minus y is equal to 5 and 3 X + 2 y is equal to 29​

Answer 1

Correct Question: Solve for x and y if 5x - y = 5 and 3x + 2y = 29.

Answer:

The value of $x=3$ and $y=10$.

Step-by-step explanation:

Consider the given equations as follows:

$5x-y=5$ . . . . . (1)

$3x+2y=29$ . . . . . (2)

Multiplying the equation (1) both the sides by the number 2 as follows:

⇒ $2(5x-y)=2\times 5$

⇒ $10x-2y=10$ . . . . . (3)

Now,

Adding the equations (2) and (3), we get

$(3x+2y)+(10x-2y)=29+10$

Simplify as follows:

⇒ $3x+10x+2y-2y=39$

⇒ $13x=39$

Dividing both the sides by $13$ as follows:

⇒ $\frac{13x}{13}=\frac{39}{13}$

⇒ $x=3$

Now, substituting the value $x=3$ in the equation (1), we get

$5(3)-y=5$

Simplify as follows:

⇒ $15-y=5$

Subtracting $15$ from both the sides, we have

⇒ $15-15-y=5-15$

⇒ $-y=-10$

⇒ $y=10$

Therefore, the value of $x$ is $3$ and the value of $y$ is $10$.

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Answer 2

Answer:

3 and 10 are the required value of x and y.

Explanation:

Given  that, 5x minus y is equal to 5 and 3x + 2y is equal to 29

This can be written as,

5x - y = 5 and

3x + 2y = 29

We solve this equation by the elimination method.

Elimination method - The elimination approach involves taking one variable out of the system of linear equations by utilizing addition or subtraction together with multiplication or division of the variable coefficients.

Step 1:

Let, 5x - y = 5 ..........(i) and

3x + 2y = 29 .............(ii)

By elimination method,

2(5x - y = 5 )

3x + 2y = 29  

13x  = 39

x = $\frac{39}{13}$ = 3

Now, we put the value of x = 3 in (i) we get,

⇒ 5x - y = 5

⇒ 5(3) - y = 5

⇒ 15 - y = 5

⇒ 15 - 5 = y

⇒ y = 10

So, x = 3 and y = 10.

Final answer:

Hence, 3 and 10 are the required value of x and y.

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