Math, asked by sharmagokul3652, 2 months ago

Solve for X -
1) 16/5x = 1/10

Answers

Answered by sahu3400u
0

Answer:

1/32

S

6

5

=

1

1

0

\frac{16}{5} \cdot x=\frac{1}{10}

516​⋅x=101​

Solve

1

Combine multiplied terms into a single fraction

1

6

5

=

1

1

0

\frac{16}{5}x=\frac{1}{10}

516​x=101​

1

6

5

=

1

1

0

\frac{16x}{5}=\frac{1}{10}

516x​=101​

2

Multiply all terms by the same value to eliminate fraction denominators

1

6

5

=

1

1

0

\frac{16x}{5}=\frac{1}{10}

516x​=101​

5

1

6

5

=

5

1

1

0

5 \cdot \frac{16x}{5}=5 \cdot \frac{1}{10}

5⋅516x​=5⋅101​

3

Cancel multiplied terms that are in the denominator

5

1

6

5

=

5

1

1

0

5 \cdot \frac{16x}{5}=5 \cdot \frac{1}{10}

5⋅516x​=5⋅101​

1

6

=

5

1

1

0

16x=5 \cdot \frac{1}{10}

16x=5⋅101​

4

Multiply the numbers

1

6

=

5

1

1

0

16x={\color{#c92786}{5}} \cdot {\color{#c92786}{\frac{1}{10}}}

16x=5⋅101​

1

6

=

1

2

16x={\color{#c92786}{\frac{1}{2}}}

16x=21​

5

Divide both sides of the equation by the same term

1

6

=

1

2

16x=\frac{1}{2}

16x=21​

1

6

1

6

=

1

2

1

6

\frac{16x}{{\color{#c92786}{16}}}=\frac{\frac{1}{2}}{{\color{#c92786}{16}}}

1616x​=1621​​

6

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

1

3

2

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