Question

Solve for x : 1/a+b+x=1/a+1/b+1/x,a not equal to 0, b not equal to 0,x not equal 0 .

Answer 1

here is ur answer ☝☝✌✌

Answer 2

AS EASY AS I THINK I AM THE GREATEST SO LET'S SOLVE

1/a+b+x=(1/a)+(1/b)+(1/x)

There's a trick in solving this question there is only one way to solve .

$\frac{1}{a + b + x} = \: \frac{1}{a} + \frac{1}{b} + \frac{1}{x} \\ \frac{1}{ a+ b + x} - \frac{1}{x} = \frac{1}{a} + \frac{1}{b} \\. \frac{x - a - b - x}{ax + bx + {x}^{2} } = \frac{a + b}{ab} \\ \frac{ - (a + b)}{ax+bx+ {x}^{2} } = \frac{a + b}{ab} \\ \frac{ - 1}{ax + bx + {x}^{2} } = \frac{1}{ab} \\ - ab = ax + bx + {x}^{2}$

now after this we will solve the quadratic equation.

x^2+ax+bx+ab=0

x(x+a)+b(x+a)=0

(x+b)(x+a)=0

x= -a

x= -b

thanks for asking

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