solve for x-: 1÷x-2 + 2÷x-1 = 6÷x (x not equal to 0,1,2)
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hi friends I am akhil. this is the answer
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1/x-2+2/x-1=6/x
x-1+2(x-2)/(x-2)(x-1)=6/x
x-1+2x-4/x2-x-2x+2=6/x
3x-5/x2-x-2x+2=6/x
x(3x-5)=6(x2-3x+2)
3x2-5x=6x2-18x+12
-3x2+13x=12
3x2-13x=-12
3x2-13x+12=0
do it cheers
x-1+2(x-2)/(x-2)(x-1)=6/x
x-1+2x-4/x2-x-2x+2=6/x
3x-5/x2-x-2x+2=6/x
x(3x-5)=6(x2-3x+2)
3x2-5x=6x2-18x+12
-3x2+13x=12
3x2-13x=-12
3x2-13x+12=0
do it cheers
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