Math, asked by gauridixit1, 9 months ago

solve for x ..................​

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Answered by Anonymous
2

Answer:

x = +3 and -3

Step-by-step explanation:

log(x+2) + log(x-2) = log5

log(x^2 - 4)= log5

(x^2 - 4)= e^log5

x^2 -4 = 5

(x - 2)*(x +2) =5

x^2 - 4 = 5

x^2 = 9

so

x= +3 and -3

Answered by kaushik05
29

 \huge \red{\mathfrak{solution}}

To find the value of x:

 \rightarrow \:  log(x - 2)  +  log(x + 2)  =  log(5)  \\  \\  \rightarrow \: log((x - 2)(x + 2))  =  log(5)  \\  \\  \rightarrow log(( {x}^{2} -  {2}^{2}  ))  =  log(5)  \\  \\  \rightarrow \: x {}^{2}  - 4 = 5 \\  \\  \rightarrow \:  {x}^{2}  = 5 + 4 = 9 \\  \\  \rightarrow \: x =  \sqrt{9}  \\  \\  \rightarrow \: x \:  = 3

Formula used :

log m + log n = log mn

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