Question

solve for x : 2/x+1 + 3/2x-4 = 23/5x where x not=to 0,-1,2

Answer 1

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Check the attachment.
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Answer 2

Answer:

x = -23/11  or x = 4

Step-by-step explanation:

Given,

$\frac{2}{x+1}+\frac{3}{2x-4}=\frac{23}{5x}$

$\frac{4x-8+3x+3}{(x+1)(2x-4)}=\frac{23}{5x}$

$\frac{7x-5}{2x^2-2x-4}=\frac{23}{5x}$

$35x^2-25x=46x^2-46x-92$

$46x^2-46x-92-35x^2+25x=0$

$11x^2-21x-92=0$

$11x^2-44x+23x-92=0$

$11x(x-4)+23(x-4)=0$

$(11x+23)(x-4)=0$

If 11 x + 23 = 0 or   x - 4 = 0

⇒ x = -23/11  or x = 4