Math, asked by ric12357, 1 year ago

solve for x :(2-x÷x-5)*2 +10x÷ x-5 -24=0

Answers

Answered by Fatimakincsem
0

The values of x are 4 and 15.

Step-by-step explanation:

{2x/(x - 5) }²   + 10x/(x - 5)   - 24  = 0

Multiplying by (x - 5)² both sides

4x² + 10x(x - 5) - 24(x - 5)² = 0

Dividing by 2 both sides

2x² + 5x(x - 5) - 12(x² -10x + 25) = 0

2x² + 5x² - 25x - 12x² + 120x - 300 =0

-5x² +95x  - 300 =0

x² - 19x  + 60 = 0

x² -4x - 15x + 60 = 0

x(x - 4) - 15(x - 4) =0

(x - 15)(x - 4) =0

x = 4 or 15

Hence the value of x is 4 and 15

Also learn more

Solve for x : (2x-3)2 = 16

https://brainly.in/question/11535318

Answered by Anonymous
0

Answer :-

The values of x are 4 and 15.

Step-by-step explanation:

{2x/(x - 5) }²   + 10x/(x - 5)   - 24  = 0

Multiplying by (x - 5)² both sides

4x² + 10x(x - 5) - 24(x - 5)² = 0

Dividing by 2 both sides

2x² + 5x(x - 5) - 12(x² -10x + 25) = 0

2x² + 5x² - 25x - 12x² + 120x - 300 =0

-5x² +95x  - 300 =0

x² - 19x  + 60 = 0

x² -4x - 15x + 60 = 0

x(x - 4) - 15(x - 4) =0

(x - 15)(x - 4) =0

x = 4 or 15

Hence the value of x is 4 and 15

Also learn more

Solve for x : (2x-3)2 = 16

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