solve for x :: 2²^x^
+1 + 4.4 ^x - 384 = 0
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Solve : 3(2x−1)
2
+4(2x−1)−4=0
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ANSWER
3(2x−1)
2
+4(2x−1)−4=0
say t=2x−1, then
⇒3t
2
+4t−4=0
⇒3t
2
+6t−2t−4=0
⇒3t(t+2)−2(t+2)=0
⇒(3t−2)(t+2)=0
∴ t=
3
2
or t=−2
⇒2x−1=
3
2
or 2x−1=−2
⇒x=
6
5
or 2x=−1
∴ x=1/2 or 5/6 or x=−1/2
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