Math, asked by tanishkas708, 7 months ago

solve for x :: 2²^x^
2 { }^{2 {x}^{ + 1} }  + 4.4 {}^{ x}  - 384 = 0
+1 + 4.4 ^x - 384 = 0

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Answered by atluri1930
2

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Solve : 3(2x−1)

2

+4(2x−1)−4=0

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ANSWER

3(2x−1)

2

+4(2x−1)−4=0

say t=2x−1, then

⇒3t

2

+4t−4=0

⇒3t

2

+6t−2t−4=0

⇒3t(t+2)−2(t+2)=0

⇒(3t−2)(t+2)=0

∴ t=

3

2

or t=−2

⇒2x−1=

3

2

or 2x−1=−2

⇒x=

6

5

or 2x=−1

∴ x=1/2 or 5/6 or x=−1/2

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