Math, asked by trinityburke, 7 months ago

Solve for x:
2x^2-13x-45=0


Please show work

Answers

Answered by Anonymous
7

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Solution :

2x²-13x-45=0

2x²-18x+5x-45=0

2x(x-9)+5(x-9)=0

(2x+5)(x-9)=0

x=-5/2 OR x=9

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Answered by swagata2k12ghosh
3

Answer:

2x^2-13x-45=0

2x^2-(18-5)x-45=0

2x^2-18x+5x-45=0

2x(x-9)+5(x-9)=0

(x-9)(2x+5)=0

then, x=9 or -5/2

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