Math, asked by joy5615, 11 months ago

solve for x: 2x^2-5x-3

Answers

Answered by AJAYMAHICH

4

Step-by-step explanation:

2x^2-5x-3 = 0

2x^2 -6x +x - 3 = 0

(2x+1)(x-3) = 0

x = -1/2 , 3

joy5615: it was given in the question

Answered by Andy07

0

2x² - 5x - 3 = 0

2x² -2x -3x -3 = 0

2x (x -1) - 3 ( x -1) =0

(2x-3) (x-1) =0

x = 1 , 3/2

plz mark it as brainliest

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