Question

solve for x:√2x²+7x+5√2=0​

Answer 1

Explaination:-

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = > \sqrt{2} {x}^{2} +2x +$

$5x + 5 \sqrt{2} = 0 = > \sqrt{2}x(x + \sqrt{2}) +$

$5(x + \sqrt{2}) =0 = >$

$( \sqrt{2}x + 5)(x + \sqrt{2}) = 0 = >$

$(x + \sqrt{2}) = 0 \: or \: ( \sqrt{2}x + 5) = 0 = >$

$x = - \sqrt{2} \: or \: - \frac{5}{ \sqrt{2}}$

Hope it helps you.