solve for x: 2xsquare-2root2x+1=0
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2x² - 2√2x + 1 = 0
2x² - √2x - √2x + 1 = 0
√2x ( √2x - 1) - 1(√2x - 1)
(√2x-1) (√2x-1) = 0
√2x - 1 = 0
x = 1/√2
x = √2/2
2x² - √2x - √2x + 1 = 0
√2x ( √2x - 1) - 1(√2x - 1)
(√2x-1) (√2x-1) = 0
√2x - 1 = 0
x = 1/√2
x = √2/2
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