solve for x: 2xsquare-2root2x+1=0
Answers
Answered by
2
2x² - 2√2x + 1 = 0
2x² - √2x - √2x + 1 = 0
√2x ( √2x - 1) - 1(√2x - 1)
(√2x-1) (√2x-1) = 0
√2x - 1 = 0
x = 1/√2
x = √2/2
2x² - √2x - √2x + 1 = 0
√2x ( √2x - 1) - 1(√2x - 1)
(√2x-1) (√2x-1) = 0
√2x - 1 = 0
x = 1/√2
x = √2/2
Similar questions
Math,
7 months ago
Social Sciences,
1 year ago