Question

solve for x: √36x+1+6√x/√36x-1-6√x=9.​

Answer 1

The value of x is 4/9.

Step-by-step explanation:

The given equation is

$\dfrac{\sqrt{36x}+1+6\sqrt{x}}{\sqrt{36x}+1-6\sqrt{x}}=9$

We need to find the value of x.

$\dfrac{6\sqrt{x}+1+6\sqrt{x}}{6\sqrt{x}+1-6\sqrt{x}}=9$

$\dfrac{12\sqrt{x}+1}{1}=9$

$12\sqrt{x}+1=9$

Subtract 1 from both sides.

$12\sqrt{x}=9-1$

$12\sqrt{x}=8$

Divide both sides by 12.

$\sqrt{x}=\dfrac{8}{12}$

$\sqrt{x}=\dfrac{2}{3}$

Taking square on both sides.

$\sqrt{x}=\dfrac{4}{9}$

Therefore, the value of x is 4/9.

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