Question

solve for x- 36x²-12ax+(a²-b²)=0

Answer 1

You have , 36x²-12ax+(a²-b²)=0 ⇒ 36x²-6(a+b+a-b)x+(a+b)(a-b)=0 ⇒ 6x(6x-(a+b)) - (a-b)(6x-(a+b))=0 ⇒ [6x-(a+b)][6x-(a-b)]=0. Then x = (a+b)/6 or (a-b)/6

Answer 2

Answer:

=(6x)²-2(6x)×a+a²-b²

=(6x-a)²-b²

using formula a²-b²= (a+b)(a-b)

=(6x-a-b)(6x-a+b)

=x=(a+b)÷6, (a-b)÷6

Hope u understood

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