Solve for x: 3root x/5+root5/x =10
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Answer:
Step-by-step explanation:
3√x/5 + √5/x = 10
squaring both side
9x/5 +5/x + 2*3(x/5)^1/2 * (x/5)^-1/2 = 100
9x/5 + 5/x + 6 = 100
(9x^2+25)/5x=100-6
9x^2 + 25=94*5x
9x^2 + 25 = 470x
9x^2 - 470x +25 = 0
by using sridharacharya method
x=(235 + 50√22)/9
x=(235 - 50√22)/9
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