Question

solve for x: 4^2x+5 =64​

Answer 1

Step-by-step explanation:

4^(2x+5) = 64

2^(4x + 10) = 2^6

Equating both sides,

4x + 10 = 6

4x = -4

x = -1

Answer 2

Answer:

$\Large\boxed{X=-1 }$

Step-by-step explanation:

Given:

4^(2x+5)=64

To solve this problem, first thing you do is isolate by the x on one side of the equation.

Solutions:

You can also used order of operations PEMDAS and BOMDAS.

BOMDAS stands for (Brackets, Of, Multiply, Divide, Add, and Subtract) the numbers from left to right.

PEMDAS stands for (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) the numbers from left to right.

First, you have to solve with exponent.

$\displaystyle 4^3=4*4*4=64$

Secondly, you have to rewrite the whole problem down.

$\displaystyle 4^{2x+5}=4^3$

$\displaystyle f(x)=a^g^(^x^)=f(x)=g(x)$

$\displaystyle 2x+5=3$

Solve.

Subtract by 5 from both sides.

$2x+5-5=3-5$

Solve.

$\displaystyle 2x=-2$

Then, divide by 2 from both sides.

$\displaystyle \frac{2x}{2}=\frac{-2}{2}$

Solve. (Simplify/find the solution.)

$\displaystyle -2\div2=\boxed{-1}$

$\Large\boxed{\boxed{X=-1 }}$

In conclusion, the correct answer is x=-1.