Math, asked by minakshikhatri91, 1 year ago

Solve for x: 5x (x+3)+1 (x+3)-8=5 (x+1)(x+2)

Answers

Answered by Anonymous
11
\huge\mathcal{Answer \ :-}

\tt\red{Given \ :-}

\mathsf{5x(x + 3) + 1(x + 3) - 8 = 5(x + 1)}
\mathsf{(x + 2)}

\mathsf{=> \ 5x^2 + 15x + x + 3 - 8 \ =}
\mathsf{5(x^2 + 2x + x + 2)}

\mathsf{=> \ 5x^2 + 16x -5 \ = \ 5x^2 + 10x + 5x}
\mathsf{+ 10}

\mathsf{=> \ 5x^2 + 16x - 5 \ = \ 5x^2 + 15x + 10}

\mathsf{=> \ 5x^2 - 5x^2 + 16x - 15x \ = \ 10 + 5}

\mathsf{=> \ x \ = \ 15}

\huge\mathfrak{Hope \ this \ helps.}

Anonymous: 3 +ve hoga 2nd step m
Anonymous: Thnx :)
Anonymous: (•ө•)♡
Answered by shiv5321
2
5x²+15x+x+3-8=5(x²+2x+x+2)
5x²+15x+x+3-8=5x²+10x+5x+10
5x²+16x-5=5x²+15x+10
16x-15x=10+5
x=15
:-) hopes this helpful for you
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