solve for x 9 x square - 6 x minus A square minus b square is equal to zero
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Given 9x2−6ax+a2−b2=0
⇒9x2−6ax+(a−b)(a+b)=0
⇒9x2−3x(a−b)−3x(a+b)+(a−b)(a+b)=0
⇒3x[3x−(a−b)]−(a+b)[3x−(a−b)]=0
⇒[3x−(a−b)][3x−(a+b)]=0
3x−(a−b)=0
3x=a−b
x=a−b/3
3x−(a+b)=0
3x=(a+b)
x=a+b/3
∴x=(a−b)/3 or x=(a+b)/3
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