Question

solve for x : 9x^2-6a^2x+(a^4-b^4)=0​

Answer 1

i hope this will help you

Answer 2

9x2 – 6a2x + (a4 – b4) = 0 ...... (1)

Here, constant term = a4 – b4 = (a2 – b2) (a2 + b2)

and coefficient of middle term = –6a2 = – {3 (a2 + b2) + 3 (a2 – b2)}

∴ equation (1) become (image with long equations

Hence the roots are (image with short equations)