Question

write balanced chemical equation

solution of pottasium iodide is added to a solution of lead nitrate​

Answer 1

ANSWER ☺️

☯️➡️Pb(NO3)2(aq) + 2KI(aq)→ PbI2(s) + 2KNO3(aq)

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Answer 2

Answer:

2KI + Pb(NO₃)₂ -----> 2KNO₃ + PbI₂

Explanation:

The formula for Potassium Iodide is KI and of Lead Nitrate is Pb(NO₃)₂.

It is a double displacement reaction so the products will be Potassium Nitrate, ie KNO₃ and Lead Iodide, ie PbI₂.

We can write it as

KI + Pb(NO₃)₂ -----> KNO₃ + PbI₂

Here, we have

K - 1                                            K - 1

I - 1                                              I - 2

Pb - 1                                          Pb - 1

N - 2                                           N - 1

O - 6                                           O - 3

If in LHS, we make I 2 from 1, we have

2KI + Pb(NO₃)₂ -----> KNO₃ + PbI₂

K - 2                                            K - 1

I - 2                                              I - 2

Pb - 1                                          Pb - 1

N - 2                                           N - 1

O - 6                                           O - 3

If in RHS, we make K 2 from 1, we have

2KI + Pb(NO₃)₂ -----> 2KNO₃ + PbI₂

K - 2                                            K - 2

I - 2                                              I - 2

Pb - 1                                          Pb - 1

N - 2                                           N - 2

O - 6                                           O - 6

Here, it is clearly seen that no. of atoms on both sides of the equation are equal. So, the equation is balanced now.