write balanced chemical equation
solution of pottasium iodide is added to a solution of lead nitrate
Answers
ANSWER ☺️
☯️➡️Pb(NO3)2(aq) + 2KI(aq)→ PbI2(s) + 2KNO3(aq)
HOPE IT HELPS ✔️
Answer:
2KI + Pb(NO₃)₂ -----> 2KNO₃ + PbI₂
Explanation:
The formula for Potassium Iodide is KI and of Lead Nitrate is Pb(NO₃)₂.
It is a double displacement reaction so the products will be Potassium Nitrate, ie KNO₃ and Lead Iodide, ie PbI₂.
We can write it as
KI + Pb(NO₃)₂ -----> KNO₃ + PbI₂
Here, we have
K - 1 K - 1
I - 1 I - 2
Pb - 1 Pb - 1
N - 2 N - 1
O - 6 O - 3
If in LHS, we make I 2 from 1, we have
2KI + Pb(NO₃)₂ -----> KNO₃ + PbI₂
K - 2 K - 1
I - 2 I - 2
Pb - 1 Pb - 1
N - 2 N - 1
O - 6 O - 3
If in RHS, we make K 2 from 1, we have
2KI + Pb(NO₃)₂ -----> 2KNO₃ + PbI₂
K - 2 K - 2
I - 2 I - 2
Pb - 1 Pb - 1
N - 2 N - 2
O - 6 O - 6
Here, it is clearly seen that no. of atoms on both sides of the equation are equal. So, the equation is balanced now.