solve for x : 9x^2 - 9(a+b)x +2a^2+5ab+2b^2 = 0
Answers
Answered by
1
Answer:
9x^2 - 9(a+b)x +2a^2+5ab+2b^2 = 0
Step-by-step explanation:
2/x+3/y-4/z=-20; 2/y-4/x+3/z=45;
3/x-4/y+2/z =52/x+3/y-4/z=-20; 2/y-4/x+3/z=45;
3/x-4/y+2/z =59x^2 - 9(a+b)x +2a^2+5ab+2b^2 = 02/x+3/y-4/z=-20; 2/y-4/x+3/z=45;
3/x-4/y+2/z =59x^2 - 9(a+b)x +2a^2+5ab+2b^2 = 02/x+3/y-4/z=-20; 2/y-4/x+3/z=45;
3/x-4/y+2/z =59x^2 - 9(a+b)x +2a^2+5ab+2b^2 = 02/x+3/y-4/z=-20; 2/y-4/x+3/z=45;
3/x-4/y+2/z =59x^2 - 9(a+b)x +2a^2+5ab+2b^2 = 0
Similar questions