Solve for x :- 9x sq + 6ax +(a sq - b sq)
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I think ur qstn is mistake ...give it correctly
UmangDobhal:
No its correct..
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Hi ,
9x² + 6ax + a² - b² = 0
9x² + 3( a + b) x + 3 (a - b) x + a²- b²=0
3x [3x + a + b ] + ( a - b ) [ 3x + a+b ]=0
( 3x + a + b ) ( 3x + a - b ) = 0
Therefore ,
3x + a + b = 0 or 3x + a - b = 0
3x = - ( a + b ) or 3x = ( b - a )
x = -( a + b ) /3 or x = ( b - a ) / 3
I hope this helps you.
:)
9x² + 6ax + a² - b² = 0
9x² + 3( a + b) x + 3 (a - b) x + a²- b²=0
3x [3x + a + b ] + ( a - b ) [ 3x + a+b ]=0
( 3x + a + b ) ( 3x + a - b ) = 0
Therefore ,
3x + a + b = 0 or 3x + a - b = 0
3x = - ( a + b ) or 3x = ( b - a )
x = -( a + b ) /3 or x = ( b - a ) / 3
I hope this helps you.
:)
brilliant
:)
Thnx its the right answer
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