solve for x a^2/x-b^2/y=0 and a^2b/x+b^2a/y=a+b
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♧♧HERE IS YOUR ANSWER♧♧
Given :
a²/x - b²/y = 0 .....(i)
and
a²b/x + b²a/y = a + b .....(ii)
Now, we multiply (i) by 1 and (ii) by 1/a.
Then,
a²/x - b²/y = 0
ab/x + b²/y = (a + b)/a
Adding, we get :
(a² + ab)/x = (a + b)/a
=> x = a²
From (i), we get :
y = b²
Therefore, the required solution be :
x = a² and y = b²
♧♧HOPE THIS HELPS YOU♧♧
Given :
a²/x - b²/y = 0 .....(i)
and
a²b/x + b²a/y = a + b .....(ii)
Now, we multiply (i) by 1 and (ii) by 1/a.
Then,
a²/x - b²/y = 0
ab/x + b²/y = (a + b)/a
Adding, we get :
(a² + ab)/x = (a + b)/a
=> x = a²
From (i), we get :
y = b²
Therefore, the required solution be :
x = a² and y = b²
♧♧HOPE THIS HELPS YOU♧♧
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