Math, asked by krutikan, 1 year ago

solve for x a^2/x-b^2/y=0 and a^2b/x+b^2a/y=a+b

Answers

Answered by Swarup1998
6
♧♧HERE IS YOUR ANSWER♧♧

Given :

a²/x - b²/y = 0 .....(i)

and

a²b/x + b²a/y = a + b .....(ii)

Now, we multiply (i) by 1 and (ii) by 1/a.

Then,

a²/x - b²/y = 0

ab/x + b²/y = (a + b)/a

Adding, we get :

(a² + ab)/x = (a + b)/a

=> x = a²

From (i), we get :

y = b²

Therefore, the required solution be :

x = a² and y = b²

♧♧HOPE THIS HELPS YOU♧♧
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