solve for x and y
105x + 107y = 116700
107x + 105y = 116500
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Let the cost price of A is Rs. x and same of B is Rs. y
Then by the given question,
(x+x×5/100)+(y+y×7/100)=1167
or,( x+x/20)+(y+7y/100)=1167
or, 21x/20+107y/100=1167
or, 105x+107y=116700 --------------(1) and
(x+x×7/100)+(y+y×5/100)=1165
or, (x+7x/100)+(y+y /20)=1165
or, 107x/100+21y/20=1165
or, 107x+105y=116500---------------(2)
Multiplying (1) with 107 and (2) with 105 we get,
11235x+11449y=12486900 ---------------(3)
11235x+11025y=12232500 ---------------(4)
Subtracting (4) from (3) we get,
424y=254400
or, y=254400/424
or, y=600
Putting in (1) we get,
105x+107×600=116700
or, 105x=116700-64200
or, 105x=52500
or, x=52500/105
or, x=500
∴, Cost price of A is Rs. 500 and cost price of B is Rs. 600
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