Math, asked by jogindernagpal28, 8 months ago

solve for x and y
148/x +231/y=527/xy
231/x+148/y=610/xy​

Answers

Answered by Anonymous
6

148/x + 231/y = 527/xy

(148y + 231x)/xy = 527/xy

148y + 231x = 527-----------( 1 )

231/x + 148/y = 610/xy

(231y + 148x)/xy = 610/xy

231y + 148x = 610------------( 2 )

adding---------( 1 ) & -----------( 2 )

231x + 148y = 527

148x + 231y = 610

---------------------------

379x + 379y = 1137

x + y = 3-----------( 3 )

subtracting-------( 1 ) &-----( 2 )

231x + 148y = 527

148x + 231y = 610

--------------------------

83x - 83y = -83

x - y = -1------------( 4 )

From-------( 3 )&-------( 4 )

x + y = 3

x - y = -1

------------

2x = 2

x = 1 [ put in -----( 3 )]

1 + y = 3

y = 2

Answered by shinuoommen79
3

Answer:

148/x + 231/y = 527/xy

(148y + 231x)/xy = 527/xy

148y + 231x = 527-----------( 1 )

231/x + 148/y = 610/xy

(231y + 148x)/xy = 610/xy

231y + 148x = 610------------( 2 )

adding---------( 1 ) & -----------( 2 )

231x + 148y = 527

148x + 231y = 610

---------------------------

379x + 379y = 1137  

x + y = 3-----------( 3 )

subtracting-------( 1 ) &-----( 2 )

231x + 148y = 527

148x + 231y = 610

--------------------------

83x - 83y = -83

x - y = -1------------( 4 )

From-------( 3 )&-------( 4 )

x + y = 3

x - y = -1

------------

2x = 2

x = 1 [ put in -----( 3 )]

1 + y = 3  

y = 2

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