solve for x and y : 2x+3y=0, 3x+4y=5
Answers
Answered by
41
2x + 3y = 0
3x + 4y = 5
3(2x+3y = 0)
2(3x+4y = 5)
6x + 9y = 0 → A
6x + 8y = 10 → B
Subtracting B from A
6x + 9y = 0
- 6x - 8y = -10
y = - 10
2x + 3(-10) = 0
2x = 30
x = 15
x = 15 and y = -10
3x + 4y = 5
3(2x+3y = 0)
2(3x+4y = 5)
6x + 9y = 0 → A
6x + 8y = 10 → B
Subtracting B from A
6x + 9y = 0
- 6x - 8y = -10
y = - 10
2x + 3(-10) = 0
2x = 30
x = 15
x = 15 and y = -10
Anonymous:
then what is right
second answer is right
second answer is also same as me
yup bro
both answers are same Bros
yup
okkk
thans bro this a is right answer
welcome
ur welcome bro
Answered by
19
this is your answer I think
Attachments:
x=15,y=-10
yup
Similar questions