solve for x and y 2x=5y+4 , 3x-2y+16=0
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Given,
2x=5y+4
2x-5y=4 ....(i)
3x-2y+16=0
-3x+2y=16 ......(ii)_
Multiplying (i) by 3 and (ii) by 2, we get
6x-15y=12 .....(iii)
-6x+4y=32 ......(iv)
Adding (iii) and (iv) we get
11y=44
y=4
Substituting the value of y in (i) we get
2x-5y=4
2x-5×4=4
2x-20=4
2x=24
x=12
Hence, x = 12, y = 4
anurag11124:
very nice..
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