Solve for x and y: 47x+3 ly = 63 and 31x+47y = 15
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Given 47x + 31y = 63 ...... &...... 31x + 47y = 15
adding both the equations we get 78x + 78y = 78
---------Dividing the equation by 78 we get
---------. x + y = 1
assume this as equation as 3
now , subtracting the first 2 equations we get
---------16x - 16y = 48
dividing the equation by 16 we get,
---------- x - y = 3
assume this as equation 4
Adding both the equations we get
2x = 4
x = 4/2
x = 2
substituting x = 2 in equation 4 we get ,
y = -1
THEREFORE X = 2 , Y = -1
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