solve for x and y 5/x+1/y=2 6/x-3/y=1
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Given 1st equation is 5/x + 1/y = 2
On cross multiplication, we get
5y + x = 2xy ----- (1)
Given 2nd equation is 6/x - 3/y = xy
On cross-multiplication, we get
6y - 3x = xy ------ (2)
On solving (1)*3 & (2), we get
15y + 3x = 6xy
6y - 3x = xy
----------------------
21y = 7xy
21y/7y = x
x = 3.
Substitute x = 3 in (1), we get
5y + x = 2xy
5y + 3 = 2(3)(y)
5y + 3 = 6y
3 = 6y - 5y
3 = y.
Therefore the value of x = 3.
the value of y = 3.
Hope this helps!
On cross multiplication, we get
5y + x = 2xy ----- (1)
Given 2nd equation is 6/x - 3/y = xy
On cross-multiplication, we get
6y - 3x = xy ------ (2)
On solving (1)*3 & (2), we get
15y + 3x = 6xy
6y - 3x = xy
----------------------
21y = 7xy
21y/7y = x
x = 3.
Substitute x = 3 in (1), we get
5y + x = 2xy
5y + 3 = 2(3)(y)
5y + 3 = 6y
3 = 6y - 5y
3 = y.
Therefore the value of x = 3.
the value of y = 3.
Hope this helps!
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