Question

Solve for x and y:6/x+y=7/x-y+3,1/2(x+y)=1/3(x-y),where x+y not equal to 0,x-y not equal to 0

Answer 1

Answer:

Step-by-step explanation:

Let : 1/(x+y)=a

1/(x-y)=b

Therefore,

1) 6a = 7b + 3

2)1/2a = 1/3b

3a = 2b

a=2b/3

From 1) and 2)

4b= 7b +3

3) b = -1

4) a= -2/3

x+y= -3/2

2x+2y=-3

2x-2y=-2

--------------

4x=-5

x=-5/4

y=-5/4 + 4/4

=-9/4

Answer 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let : 1/(x+y)=a

1/(x-y)=b

Therefore,

1) 6a = 7b + 3

2)1/2a = 1/3b

3a = 2b

a=2b/3

From 1) and 2)

4b= 7b +3

3) b = -1

4) a= -2/3

x+y= -3/2

2x+2y=-3

2x-2y=-2

--------------

4x=-5

x=-5/4

y=-5/4 + 4/4

=-9/4