Question

Solve for x and y


631x + 279y = 190
279x + 631y = 910
Class 10 pair of linear equations

Answer 1

Correct your question it's 631x+279y=910 and 279x+631y=910

Answer 2

Answer:

$\text{The solution is }(-\frac{1675}{4004},\frac{6515}{4004})\text{ i.e }(-0.418, 1.627)$

Step-by-step explanation:

Given two equations

$631x + 279y = 190$

$279x + 631y = 910$

we have to solve the above two equations

Adding above two equations

$631x + 279y + 279x + 631y = 190+910$

$910x+910y=1100$

$x+y=\frac{1100}{910}$ →  (1)

Subtracting above two equations

$631x + 279y - 279x - 631y = 190-910$

$352x-352y=-720$

$x-y=-\frac{720}{352}$ →  (2)

By elimination method

Solving equation (1) and (2)

$2x=\frac{1100}{910}-\frac{720}{352}=-\frac{1675}{2002}$

$x=-\frac{1675}{4004}=-0.418$

$2y=\frac{1100}{910}+\frac{720}{352}=\frac{6515}{2002}$

$y=\frac{6515}{4004}=1.627$

$\text{Hence, the solution is }(-\frac{1675}{4004},\frac{6515}{4004})\text{ i.e }(-0.418, 1.627)$