solve for x and y 8/2x-3y+21/2x+3y=11; 5/2x-3y+7/2x+3y=6
Answers
Answer:
x = 17/10 and y = any value or 0
Step-by-step explanation:
8/2x - 3y + 21/2x + 3y = 11 ---- Eq. 1
5/2x - 3y + 7/2x + 3y = 6 ---- Eq. 2
Subtract both the equations ( Since - 3y and 3y can be subtracted in order to obtain only one variable i.e. x )
8/2x - 3y + 21/2x + 3y = 11
5/2x - 3y + 7 /2x + 3y = 6 (-)
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3/2x + 14/2x = 5 ---- Eq. 3
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From Eq. 3, We have to solve to get value of x
3/2x + 14/2x = 5
17/2x = 5
x = 17/10
Now for value y for both equations it can be any value because you value cancels for both equations anyway.
It can be solved in many other methods but this is one of the proper methods, but anyways thank you ❤!!
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