Solve for x and y
a^2x+b^2 y=c^2-eq.1 b^2x+a^2y=d^2-eq.2
Answers
Answered by
1
multiply eq 1 by b*b.
multiply eq 2 by a*a
and subtract it
you will get your answer
multiply eq 2 by a*a
and subtract it
you will get your answer
Answered by
2
a2 x + b2 y = c2 --- ( 1 )
And
b2 x + a2 y = d2 --- ( 2 )
Now we multiply by a2 in equation 1 and by b2in equation 2 and get
a4 x + a2 b2 y = a2c2 --- ( 3 )
And
b4 x + a2 b2 y = b2d2 --- ( 4 )
Now we subtract equation 4 from equation 3 and get
a4 x - b4 x= a2c2 - b2 d2
( a4 - b4 ) x= a2c2 - b2 d2
x = a2c2 − b2d2 a4 − b4
And we multiply by b2 in equation 1 and by a2in equation 2 and get
a2 b2 x + b4 y = b2c2 --- ( 5 )
And
a2 b2 x + a4 y = a2d2 --- ( 6 )
Now we subtract equation 5 from equation 6 and get
a4 y - b4 y= a2d2 - b2 c2
( a4 - b4 ) y = a2d2 - b2 c2
y = a2d2 − b2c2 a4 − b4
Therefore,
x = a2c2 − b2d2 a4 − b4 and y = a2d2 − b2c2 a4 − b4
And
b2 x + a2 y = d2 --- ( 2 )
Now we multiply by a2 in equation 1 and by b2in equation 2 and get
a4 x + a2 b2 y = a2c2 --- ( 3 )
And
b4 x + a2 b2 y = b2d2 --- ( 4 )
Now we subtract equation 4 from equation 3 and get
a4 x - b4 x= a2c2 - b2 d2
( a4 - b4 ) x= a2c2 - b2 d2
x = a2c2 − b2d2 a4 − b4
And we multiply by b2 in equation 1 and by a2in equation 2 and get
a2 b2 x + b4 y = b2c2 --- ( 5 )
And
a2 b2 x + a4 y = a2d2 --- ( 6 )
Now we subtract equation 5 from equation 6 and get
a4 y - b4 y= a2d2 - b2 c2
( a4 - b4 ) y = a2d2 - b2 c2
y = a2d2 − b2c2 a4 − b4
Therefore,
x = a2c2 − b2d2 a4 − b4 and y = a2d2 − b2c2 a4 − b4
Similar questions