Question

solve for X and y ax+by-2a+3b=0 and bx -ay=3a+2b

Answer 1

given,
ax+by-2a+3b=0...............................(1)+
bx-ay=3a+2b....................................(2)
from equation (2) ,
bx-ay-3a-2b=0............................(3)
multiplying equation (1) by b and equation (2) by a
abx+b^2y-2ab+3b^2=0.......................(4)
abx-a^2y-3a^2-2ab=0...........................(5)a
subtracting eq (5) from (4)
abx+b^2y-2ab+3b^2=0
-abx+a^2y+3a^2+2ab=0
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0+y(a^2+b^2)+3(a^2+b^2)=0
(a^2+b^2)(y+3)=0
y+3=0
y=-3
put in equation 1 ,
ax-3b-2a+3b=0
ax-2a=0
a(x-2)=0
x-2=0
x=2