Math, asked by pikachu29, 10 months ago

solve for x and y by any algebraic method 7(y+3)-2(x+2)=14and 4 ( y-2) +3(x-3)=2
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Answers

Answered by mdsk1
1

hope it will help..........

Attachments:
Answered by nandini7451
1

7y+21-2x+4=14

7y-2x+21+4-14=0

7y-2x+7=0

7y-2x=-7(equation1)

4y-8+3x-9=2

4y+3x-8-9-2=0

4y+3x-19=0

4y+3x=19(equation2)

multiplying the equation

7y-2x=-7*4

4y+3x=19*7

---------------------

28y-14x=-28

28y+21x=133

- - -

---------------------

0-35x=-161

x=-161/-35

x=161/35

putting the value of x in equation 1

7y-2x=-7

7y-2*161/35=-7

7y-332/35=-7

245y-332

--------------------=-7

35

245y-332=-245

245y=-245+332

245y=87

y=87/245

the value of

x=161/35

y=87/245

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