Math, asked by ashishtiwari14, 1 year ago

solve for x and y: jskskkaka

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Answers

Answered by digi18
1
(32)^x/2 = 2^y + 1

(2)^5×x/2

2^5x/2 = 2^y +1

Bases are same so equate the power

5x / 2 = y + 1

5x = 2y + 2

5x - 2y = 2. eq1

Now for 2nd equation

16^(8-x) / 2 = 8^y

2^4(8 - x)/2 = 2^3y

Now bases are same so equate the power

2(8 - x) = 3y

16 - 2x = 3y

2x + 3y = 16. eq 2
5x - 2y = 2. eq 1

so multiply eq 1 by 3 and eq2 by 2

15x - 6y = 6
4x + 6y = 32

19x = 38

x = 38 / 19 = 2

Put x in eq1

5 × 2 - 2y = 2

- 2y = 2 - 10

y = -8 / -2

y = 4

So x = 2 and y = 4

Thanks

ashishtiwari14: thanks bhai
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