solve for x and y ,,,
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x = 14
y = 9
step-by-step explanation:
Given,
x/7 + y/3 = 5
=> (3x + 7y)/7×3 = 5
doing cross multiplication,
we get,
=> 3x + 7y = 21×5
=> 3x + 7y = 105
multiplying the equation with 3,
we get,
=> 9x + 21y = 315 ..............(i)
and
x/2 - y/9 = 6
=> (9x -2y)/9×2 = 6
doing cross multiplication,
we get,
=> 9x - 2y = 18×6
=> 9x - 2y = 108 ............(ii)
now,
subtracting eqn(ii) from eqn (i),
we get,
21y- (-2y) = 315 - 108
=> 23y = 207
=> y = 207/23
=> y = 9
now putting the value of y in eqn (ii),
we get,
9x - 2×9 = 108
=> 9x = 108+ 18
=> 9x = 126
=> x = 126/9
=> x = 14
Hence,
x = 14
y = 9
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