Solve for x and Y using substitution method
X + Y = 3
4x - 3y = 26
Answers
Answered by
25
Hey!!
x + y = 3 -------(1)
4x - 3y = 26 --------(2)
From eq'n (1) we get
x + y = 3
=> y = 3 - x -------( 3 )
Substitute eq'n ( 3 ) in eq'n ( 2 ) we get
4x - 3y = 26
=> 4x - 3 ( 3 - x ) = 26
=> 4x - 9 + 3x = 26
=> 7x = 26 + 9
=> 7x = 35
=> x = 5 >>>> Answer
From eq'n ( 3 ) we get
y = 3 - x
=> y = 3 - 5
=> y = - 2 >>>> Answer
Therefore the value of x = 5 and value of y = - 2
Hope it will helps you ✌
x + y = 3 -------(1)
4x - 3y = 26 --------(2)
From eq'n (1) we get
x + y = 3
=> y = 3 - x -------( 3 )
Substitute eq'n ( 3 ) in eq'n ( 2 ) we get
4x - 3y = 26
=> 4x - 3 ( 3 - x ) = 26
=> 4x - 9 + 3x = 26
=> 7x = 26 + 9
=> 7x = 35
=> x = 5 >>>> Answer
From eq'n ( 3 ) we get
y = 3 - x
=> y = 3 - 5
=> y = - 2 >>>> Answer
Therefore the value of x = 5 and value of y = - 2
Hope it will helps you ✌
TANU81:
^_^
Answered by
13
♥️Hi there ♥️
By substitution method .
From equation 1 ,
x = 3 - y --------(3)
Now put this in equation 1
Now put it in equation 3
x = 3 - (-2)
x = 3 +2
x =5
Now for elimination method ,
Multiply 3 in first eqn so that 3y can eliminate and multiply 1 from 2
Now , add both the eqn
Thanks !!!☺️
Hope it will helpful .
By substitution method .
From equation 1 ,
x = 3 - y --------(3)
Now put this in equation 1
Now put it in equation 3
x = 3 - (-2)
x = 3 +2
x =5
Now for elimination method ,
Multiply 3 in first eqn so that 3y can eliminate and multiply 1 from 2
Now , add both the eqn
Thanks !!!☺️
Hope it will helpful .
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