solve for x and y
y/2 + x = 4
2y + x/3 = 5
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The given pair of equations are: x + y/2 = 4 …………(i) 2y + x/3 = 5…………(ii) From (i) we get, x + y/2 = 4 ⇒ 2x + y = 8 [After taking LCM] ⇒ y = 8 – 2x …..(iv) From (ii) we get, x + 6y = 15 …………(iii) [After taking LCM] Substituting y in (iii), we get x + 6(8 – 2x) = 15 ⇒ x + 48 – 12x = 15 ⇒ -11x = 15 – 48 ⇒ -11x = -33 ⇒ x = 3 Putting x = 3 in (iv), we get y = 8 – (2 x 3) ∴ y = 8 – 6 = 2 Hence, the solution of the given system of equation are x = 3 and y = 2 respectively.Read more on Sarthaks.com - https://www.sarthaks.com/625424/solve-the-following-system-of-equations-x-y-2-4-2y-x-3-5
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Answer:
i) 8
ii)15/2
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