Question

Solve for x. ax2 + (4a2 - 3b)x - 12ab = 0

Answer 1

I hope this will help you......

Answer 2

Answer:

The values of x are $x=-4a,\frac{3b}{a}$

Step-by-step explanation:    

Given : Expression $ax^2+(4a^2-3b)x-12ab=0$

To find : Solver for x?

Solution :  

Expression $ax^2+(4a^2-3b)x-12ab=0$

Applying middle term split,

As middle term is divided into two term such that their multiplication became the product of x² coefficient and constant term and their addition became term of coefficient of x.

$ax^2+4a^2x-3bx-12ab=0$

$ax(x+4a)-3b(x+4a)=0$

Taking common,

$(x+4a)(ax-3b)=0$

$(x+4a)=0,(ax-3b)=0$

$x=-4a,x=\frac{3b}{a}$

Therefore, The values of x are $x=-4a,\frac{3b}{a}$