Solve for x : ax2 + (4a2 - 3b)x -12ab = 0
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Answered by
8
ax2+4a2x-3bx-12ab=0
ax(x+4a)-3b(x+4a)=0
(x+4a)(ax-3b)=0
x=-4a. ax-3b=0
ax=3b x=3b/a
ax(x+4a)-3b(x+4a)=0
(x+4a)(ax-3b)=0
x=-4a. ax-3b=0
ax=3b x=3b/a
Answered by
0
ax^2 + (4a^2 - 3b)x - 12ab = 0
ax^2 + 4a^2x - 3bx - 12 ab = 0
ax(x + 4a ) - 3b(x + 4a ) =0
(x + 4a ) (ax - 3b) =0
x + 4a = 0 OR ax - 3b = 0
x = -4a OR x = 3b/a
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