Question

solve for x
[i]x^-2=9
[ii]4^x=32
[iii]9×3^x-1=1/27​

Answer 1

Answer:

Ii) 11

ii) 8

iii) 2

Step-by-step explanation:

i) x^-2=9

x = 9+2

x = 11

ii) 4^x=32

x=32/4

x=8

iii) 9×3^x-1=1/27

27 ^x -1 =1/27

x-1 =1/27×27

x-1 = 1

x= 1+1

× =2

I hope this helps you

Answer 2

Answer:

$i ) x^-2 = 9$

$=> 1/x² = 9$

$=> 1 = 9x²$

$=> x² = 1/9$

$=> x = 1/3$

$ii ) 4^x = 32$

$=> 2^2x = 2^5$

$=> 2x = 5$

$=> x = 2.5$

$iii ) 9×3^x-1=1/27$

$=> 3² × 3^x-1 = 3^-³$

$=> 2 + x - 1 = -3$

$=> x = -4$

Step-by-step explanation:

$<marquee> Hope it helps you ...$