Question

solve for x if 2(x+1) (x-3)+5(x-2)(x+1)+(x+1)(x-2)=0​

Answer 1

Answer:

hello friends.....good evening...

Answer 2

$2(x + 1)(x - 3) + 5(x - 2)(x + 1) + (x + 1)(x - 2) = 0 \\ 2( {x}^{2} - 3x + x - 3) + 5( {x}^{2} + x - 2x - 2) + {x}^{2} - 2x + x - 2 = 0 \\ 2( {x}^{2} - 2x - 3) + 5( {x}^{2} - x - 2) + {x}^{2} - 2x + 2 = 0 \\ 2 {x}^{2} - 4x - 6 + 5 {x}^{2} - 5x - 10 + {x}^{2} - 2x + 2 = 0 \\ 2 {x}^{2} + 5 {x}^{2} + {x}^{2} - 4x - 5x - 2x - 6 - 10 + 2 = 0 \\ 8 {x}^{2} - 11x - 14 = 0$